Self-adjoint operator

Definition: In a finite dimensional space, given any linear operator \; A defined on the whole space, there exists an operator \; A^\dagger such that

\; \langle \phi, A\chi \rangle = \langle A^\dagger\phi, \chi \rangle, \quad \phi, \chi \in \mathcal{H}.

\; A^\dagger is uniquely determined and is called the adjoint of \; A.


It must be noticed that for bounded operators the adjoint operator can be defined naturally, whereas for unbounded operators this can be done only if the domain of \; A, \; \mathcal{D}(A), is dense in \; \mathcal{H} and only for those vectors \; \phi for which \; \langle \phi, A\chi \rangle is a continuous function of \; \chi. The set of these vectors is a vectorial subset of \; \mathcal{H} and by definition it will be the domain, \; \mathcal{D}(A^\dagger), of \; A^\dagger.


Definition: A linear operator \; A is said to be:

  1. a Hermitian operator if \; A \subseteq  A^\dagger, i.e. if
\; \langle \phi, A\phi \rangle = \langle A\phi, \phi \rangle, \quad \phi \in \mathcal{D}(A) ;
  1. a symmetric operator if \; A \subseteq  A^\dagger and \; \overline{\mathcal{D}(A) }=\mathcal{H}, where \; \overline{\mathcal{D}(A) } is the complement of \; {\mathcal{D}(A) };
  2. a self-adjoint operator if \; A =  A^\dagger and \; \overline{\mathcal{D}(A) }=\mathcal{H}.

For bounded linear operators, and in particular for linear operators in finite dimensional Hilbert spaces, the three definitions coincide.


Proposition: A necessary and sufficient condition for the linear operator \; A to be Hermitian is that

\; \langle \phi, A\chi \rangle = \langle A\phi, \chi \rangle, \quad \phi, \chi \in \mathcal{H}.

Proof: This equality certainly implies the definition 1. of Hermitian operator. The converse is true because of the following identity, which can be easily verified:

\; 4\langle \phi, A\chi \rangle = \langle \phi+\chi, A(\phi+\chi) \rangle  \langle \phi-\chi, A(\phi-\chi) \rangle -i\langle \phi+i\chi, A(\phi+i\chi) \rangle + i\langle \phi-i\chi, A(\phi-i\chi) \rangle.


The matrix which represents the adjoint of a linear operator \; A in any orthonormal basis is the Hermitian conjugate of the matrix representing \; A. Indeed its matrix elements are given by:

\; A_{m,n}^* = \langle \xi_m, A\xi_n\rangle^* = \langle A^\dagger\xi_m, \xi_n\rangle^* = \langle \xi_n, A^\dagger\xi_m\rangle = A_{n,m}^\dagger.

So, if a bounded linear operator is self-adjoint, it is represented by a Hermitian matrix in any orthonormal basis.